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; The first thing we discover is that, no matter how we hint it, the optimizer will stubbornly produce the following plan if either the emp.dept_no or dept.dept_no is allowed to be null. Something is blocking any transformation if nulls are allowed (we will examine this in a minute). Execution Plan (9.2.0.6 autotrace) ---------------------------------------------------------0 SELECT STATEMENT Optimizer=ALL_ROWS (Cost=2035 Card=1000 Bytes=72000) 1 0 FILTER 2 1 TABLE ACCESS (FULL) OF 'EMP' (Cost=35 Card=1000 Bytes=72000) 3 1 TABLE ACCESS (FULL) OF 'DEPT' (Cost=2 Card=1 Bytes=5) If we want the optimizer to be clever with not in subqueries, we need to ensure that the columns at both ends of the comparison may not be null. Of course, one way of doing this is to add a not null constraint to the two columns but adding a predicate dept_no is not null at both ends of the query would also work. Assuming that we do have the necessary not null constraints at both ends of the comparison, we get the following extra execution plans from 9i (in my case the hash anti-join appeared as the default action, the other two options had to be hinted): Execution Plan (9.2.0.6 - with nl_aj hint in subquery) ---------------------------------------------------------0 SELECT STATEMENT Optimizer=ALL_ROWS (Cost=40035 Card=10000 Bytes=770000) 1 0 NESTED LOOPS (ANTI) (Cost=40035 Card=10000 Bytes=770000) 2 1 TABLE ACCESS (FULL) OF 'EMP' (Cost=35 Card=20000 Bytes=1440000) 3 1 TABLE ACCESS (FULL) OF 'DEPT' (Cost=2 Card=2 Bytes=10) rdlc pdf 417 PDF417 Barcode Creating Library for RDLC Reports | Generate ...
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Free trial package available to insert PDF - 417 barcode image into Client Report RDLC . Execution Plan (9.2.0.6 - with merge_aj hint in subquery) ---------------------------------------------------------0 SELECT STATEMENT Optimizer=ALL_ROWS (Cost=282 Card=10000 Bytes=770000) 1 0 MERGE JOIN (ANTI) (Cost=282 Card=10000 Bytes=770000) 2 1 SORT (JOIN) (Cost=274 Card=20000 Bytes=1440000) 3 2 TABLE ACCESS (FULL) OF 'EMP' (Cost=35 Card=20000 Bytes=1440000) 4 1 SORT (UNIQUE) (Cost=8 Card=3 Bytes=15) 5 4 TABLE ACCESS (FULL) OF 'DEPT' (Cost=2 Card=3 Bytes=15) Execution Plan (9.2.0.6 - with hash_aj hint in subquery) ---------------------------------------------------------0 SELECT STATEMENT Optimizer=ALL_ROWS (Cost=63 Card=10000 Bytes=770000) 1 0 HASH JOIN (ANTI) (Cost=63 Card=10000 Bytes=770000) 2 1 TABLE ACCESS (FULL) OF 'EMP' (Cost=35 Card=20000 Bytes=1440000) 3 1 TABLE ACCESS (FULL) OF 'DEPT' (Cost=2 Card=3 Bytes=15) And you notice once more in 9i that the hash join has been done the expensive way (hashing the larger table). Again, 10g comes to the rescue with the following execution plan where the table order has been reversed, and the (anti) has been replaced by (right anti): Execution Plan (10.1.0.4 - with hash_aj hint in subquery) ---------------------------------------------------------0 SELECT STATEMENT Optimizer=ALL_ROWS (Cost=38 Card=10000 Bytes=770000) 1 0 HASH JOIN (RIGHT ANTI) (Cost=38 Card=10000 Bytes=770000) 2 1 TABLE ACCESS (FULL) OF 'DEPT' (TABLE) (Cost=2 Card=3 Bytes=15) 3 1 TABLE ACCESS (FULL) OF 'EMP' (TABLE) (Cost=35 Card=20000 Bytes=1440000) We can explain the anti-join by thinking how we could rewrite the not in subquery as a join. The following query is an appropriate rewrite, and gives us the critical clue as to how the anti-join is behaving: select emp.* from emp, dept where and and ; dept.dept_no(+) = emp.dept_no dept.dept_group(+) = 2 dept.dept_no is null rdlc pdf 417 How to add Barcode to Local Reports ( RDLC ) before report ...
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